Question

what the answer plz say me I'm in 10th

Answer 1

Hope this will help you

Answer 2

$a = 3 \\ b = - k \sqrt{3} \\ c = 4 \\ d = b {}^{2} - 4ac \\ = ( - k \sqrt{3} ) - 4(3)(4) = 0 \\ 3k {}^{2} - 48 = 0 \\ 3k {}^{2} = 48 \\ k {}^{2} = \frac{48}{3}k {}^{2} = 16 \\ k = \sqrt{16} \\ k = +4$
or k = -4