If alpha and beta are the zeroes of quadartic polynomial p(x)=csqare -x-2 find apolynomial whose zeroes are 2alpha+1and 2beta +1
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Step-by-step explanation:
(∝+1)(β+1)
∝+β=-b by a
=-(-4) by 1 =4
∝+β=4
∝β=c by a
=3 by 1 =3
∝β = 3
Then , multiply ∝+1 into the second bracket with both the no.s
multiply β+1 into the first bracket with both the no.s
= ∝β + ∝ + β +1
Now substitute the values in this above equation,
=3+4+1
=8
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shaziasaleemshaik3:
This is for the equation tsquare -4t+3
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