if alpha and beta are the zeroes of quadratic equation then evaluate: Alpha^2/beta+beta^2/alpha
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Answer:
Given quadratic polynomial is f(x)=ax
2
+bx+c
The zeroes of the polynomial are αβ
Sum of the zeros =−
a
b
α+β=>−
a
b
Poduct of the zeros=
a
c
αβ=>
a
c
Now,
α+β=>−
a
b
Squaring both sides,
=>(α+β)
2
=−(
a
b
)
2
=>α
2
+β
2
+2αβ=
a
2
b
2
=>α
2
+β
2
+2(
a
c
)=
a
2
b
2
=>α
2
+β
2
=
a
2
b
2
−
a
2c
=>α
2
+β
2
=
a
2
b
2
−2ca
=>α
2
+β
2
=
a
2
b
2
−2ac
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