Question

If alpha and beta are the zeroes of quadratic polynomials 4x^2+3x+7,then find the values of alpha square plus Beeta square
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Answer 1

4x^2+3x+7=0 is the quadratic equation given.

So here,

α+β=-3/4 and αβ=7/4

And we have to find out the value of α^2+β^2

It can be written as (α+β)^2-2(αβ)

So on putting the values, we have,

(-3/4)^2-2(7/4)

9/16-7/2= 9-56/16 = -47/16

So, the answer comes out to be -47/16