Question

If alpha and beta are the zeroes of the polynomial 5y2-7y+1 find the value of 1/alpha + 1/beta

Answer 1

Given f(x) = 5y^2 - 7y + 1.

Given that a,b be the zeros of the polynomial.

We know that sum of zeroes = -b/a

= > a + b = -(-7/5)

= > a + b = 7/5.


We know that product of zeroes = c/a

= > ab = 1/5


Now,

= > 1/a + 1/b = (a + b)/ab

                    = (7/5) * (5/1)

                    = 7/1

                    = 7.



Hope this helps!

Answer 2

Answer:

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Step-by-step explanation:

we know that sum is -b/a = 7/5 .......1

and product is c/a = 1/5..........2

alpha and beta are zeros of the polynomial

alpha + beta = -b/a

alpha × beta = c/a

1/alpha + 1/beta = (alpha + beta)/(alpha × beta)

From eq 1 and eq 2

= 7/5 ÷ 1/5

= 7/5 × 5

= 7

therefore answer is 7

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