if alpha and beta are the zeroes of the polynomial f (x) = 2x2+11x +5 , then find 1/alpha +1/beta -2alpha betta
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2x^2+11x+5
=2x^2+10x+x+5
=2x(x+5)+1(x+5)
=(X+5)(2x+1)
Therefore,
X+5=0.
=x= -5(alpha) 2x+1=0 = X= -1/2(beta)
Now
1/alpha+1/beta-2alpha
=1/-5+1/1/2-2(-5)
=1/5+2+10
=(-1+10+50)/5
=59/5(ans)
=2x^2+10x+x+5
=2x(x+5)+1(x+5)
=(X+5)(2x+1)
Therefore,
X+5=0.
=x= -5(alpha) 2x+1=0 = X= -1/2(beta)
Now
1/alpha+1/beta-2alpha
=1/-5+1/1/2-2(-5)
=1/5+2+10
=(-1+10+50)/5
=59/5(ans)
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