Math, asked by Anonymous, 1 year ago

if alpha and beta are the zeroes of the polynomial f(x)=x^2-6x+k, then find the value of k, such that apha^2+ beta^2= 40

Answers

Answered by shobaradkrish
0

Answer:

α+β = -b/a = -(-6)/1 =6

αβ =c/a =k/1 =k

now its given that

α²+β² =40

(α+β)² - 2αβ =40  

substituting the values we get ,

(6)² -2k =40

36-2k =40

2k = 4

k =2

hope this helps u .......

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