Question

If alpha and beta are the zeroes of the polynomial f(x)=x^2-6x+k, then find the value of k, such that apha^2+ beta^2= 40

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Answer:

Step-by-step explanation:

According to the question,α+β=6 (-b/a);αβ=k(c/a)

α$x^{2}$+β$x^{2}$=40

a$x^{2}$+b$x^{2}$=(a+b)$x^{2}$-2ab=6$x^{2}$-2k=40

36-2k=40

-2k=4

k=-2

Hence,the value of k is -2