Question

if alpha and beta are the zeroes of the polynomial f(x)=x2- p(x+1)-c such that (alpha+1)(p+1)=0 then

Answer 1

Step-by-step explanation:

not idea this question

Answer 2

If alpha and beeta are zeroes of polynomial x2-p(x+1)+c such that (alpha+1)

 

Given that alpha and beta are the roots of the quadratic equation  f(x) = x^2-p(x+1)-c = x^2-px-p-c = x^2 -px-(p+c), 

comparing with ax^2 + bx + c, we have, a =1 , b= -p & c= -(p+c) 

alpha+beta = -b/a = -(-p)/1 = p 

& alpha*beta = c/a = -(p+c)/1 = -(p+c) 

Therefore, (Alpha + 1)*(beta+1)  

= Alpha*beta + alpha + beta + 1  

= -(p+c) + p + 1 

= -p-c+p+1 

= 1-c

or c=1