If alpha and beta are the zeroes of the polynomial p (x) = 5x²+5x+1 find the value of 1/alpha ²+1/beta², 1/alpha +1/beta - 2 alpha beta, alpha ²+beta ².
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Answer:
The given polynomial is
p (x) = 5x² + 5x + 1
Since α and β are the zeroes of p (x),
α + β = - 5/5
⇒ α + β = - 1 ...(1)
and
αβ = 1/5 ...(2)
(i) Now, α² + β²
= (α + β)² - 2αβ
= (- 1)² - 2 (1/5)
= 1 - 2/5
= (5 - 2)/5
= 3/5
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