if alpha and beta are the zeroes of the polynomial x^2-5x+6 find the value of alpha^3+beta^3
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Answer:
x∧2-5x+6
on equating
ax∧2+bx+c
we get, a=1 ,b= -5, c=6
α+β= -b/a= -(-5)/1= 5 --1
αβ= c/a =6/1= 6 --2
α∧3+β∧3= (α+β) (α∧2+β∧2 -αβ)=(α+β) ((α+β)∧2-2αβ-αβ)
α∧3+β∧3=(5) (5∧2-3×6) = 5×(25-18) = 5×7=35
Step-by-step explanation:
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