Question

If alpha and beta are the zeroes of the polynomial x^2-7x+10, then find the value of(alpha+ beta)^2- (alpha)( beta)

Answer 1

Answer:

x^2-7x+10

x² - 5x -2x +10 { splitting the middle term }

x{x-5} - 2{x-5}

{x-5}{x-2}

alpha= x-5 =0

alpha = 5

beta =x-2=0

beta =2

alpha+ beta)²- (alpha)( beta)

{5+2}² - 5×2

7² - 10

49 - 10

=39

hope it helps :)