If alpha and beta are the zeroes of the polynomials x^2 -6x +k and 3 alpha +2beta = 20. Find k
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Given,
α and β are the zeroes of the polynomial x² - 6x + k
∴α + β = -(-6)/1 = 6
Also,
αβ = k/1 = k
Now,
3α + 2β = 20
⇒ 3(6) + 2(k) = 20
⇒ 18 + 2k = 20
⇒ 9 + 2k = 10
⇒ 2k = 1
⇒ k = 1/2
α and β are the zeroes of the polynomial x² - 6x + k
∴α + β = -(-6)/1 = 6
Also,
αβ = k/1 = k
Now,
3α + 2β = 20
⇒ 3(6) + 2(k) = 20
⇒ 18 + 2k = 20
⇒ 9 + 2k = 10
⇒ 2k = 1
⇒ k = 1/2
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