If alpha and beta are the zeroes of the quadratic polynomial p(x)=6x²+x-2 then find the value of alpha-beta, alpha²+beta², 1/alpha+1/beta alpha beta²+alpha²beta
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solutions:-
(1) α-β = √29/6
(2) α²+β² = 25/36
(3) 1/α+1/β = 2
(4)αβ²+α²β = 1/18
Explain:-
p(x)=6x²+x-2
α+β = -1/6 αβ = -1/3
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