if alpha and beta are the zeroes of the quadratic polynomial f(x)=x^-4x+3 find the value of alpha
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sum=-4
product =3
so the only set of no.s that satisfy above is -1,-3
x^2-x-3x+3=0
taking common factors
x(x-1)-3(x-1)=0
(x-1)(x-3)=0
if it has to be 0 either of then have to be zero. equating both to 0
x=1and x=3
hence alpha can be 1,3
bhagath71:
how old are you
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