If alpha and beta are the zeroes of the qudratic polynomial f(x)=ax square+bx+c, then evaluate: 1- alpha square+beta square 2- alpha/beta+beta/alpha 3- alpha cube+beta cube
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given that alpha , beta are zeroes
alpha + beta=-b/a
hence, alpha + beta =-b/a-(i)
alpha×beta=c/a-(ii)
alpha + beta=-b/a
hence, alpha + beta =-b/a-(i)
alpha×beta=c/a-(ii)
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