Question

If alpha and beta are the zeroes of x^2-x-6 find the value of 1/3*alpha + 1/3*beta

Answer 1

Answer:

x²-x-6

x²+2x-3x-6

x(x+2)-1(x+2)

(x+2)(x-1)

x=-2,x=1

1/3(1)+1/3(-2)

1/3+1/(-6)

2-1/6

1/6