if alpha ans bita are zeros of quardiatic polynomial f(x)=4x2-4x+1,find the value of alpha/bita +bita /alpha
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alpha/ bita + bita/ alpha
[(alpha)2+(bita)2] /alpha.bita
[(alpha + bita)2-2alpha bita ] /alpha.bita
such that ......
alpha.bita= c/a
=1/4
alpha+bita= -b/a
=4/4=1
[(1)2-2(1/4)] /1/4
=(1-1/2) /1/4
1/2*4
=2
this is answer
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