Question

If Alpha and Beta are the zeroes of x2 + 5x + 6, find the values of alpha-1 +beta-1.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

$\boxed{\tt \alpha - 1 + \beta - 1 = -7}$

Step-by-step explanation:

Given that -

• α and β are the zeroes of the quadratic polynomial x² + 5x + 6.

We know that,

The standard form of the quadratic polynomial is ax² + bx + c. Here,

• a = 1
• b = 5
• c = 6

Sum of zeroes = $\sf \dfrac{-(coefficient \: of \: x)}{coefficient \: of \: x^2}$

⇒ α + β = $\dfrac{-(5)}{1}$

⇒ α + β = - 5

Product of zeroes = $\sf \dfrac{constant \: term}{coefficient \: of \: x^2}$

⇒ αβ = $\dfrac{6}{1}$

⇒ αβ = 6

To find :

= α - 1 + β - 1

= α + β - 2

= - 5 - 2

= - 7

Hence, the answer is -7.