Question

if alpha and beta are the zeros of f of X is equals to K X square + 4 x + 4 such that Alpha square + beta square is equals to 24 find k​

Answer 1

hey mate

here is your answer

if alpha and beta are zeros of f(x)=kx^2+4x+4

alpha + beta =-b/a =-4/k

alpha×beta=c/a = 4/k

${( \alpha + \beta )}^{2} = { \alpha }^{2} + { \beta }^{2} + 2 \alpha \beta \\ {( \frac{ - 4}{k} )}^{2} = { \alpha }^{2} + { \beta }^{2} + 2 \alpha \beta \\ \frac{16}{ {k}^{2} } = 24 + \frac{8}{k} \\ 16 = 24 {k}^{2} + 8k \\ 24 {k}^{2} + 8k - 16 = 0 \\ 3 {k}^{2} + k - 2 = 0 \\ 3 {k}^{2} + 3k - 2k - 2 = 0 \\ 3k(k + 1) - 2(k + 1) = 0 \\ k = - 1 \:a n d\: \frac{2}{3}$

hope it helps

Answer 2

heyyy mate ur answer is here

Hope this willl help uhh