Question

if alpha and beta are the zeros of f(x)=x²-p(x+1)-c then (alpha+1)(beta+1) is equal to.

Answer 1

Hey!

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Given,

Alpha and beta are the zeroes of the quadratic polynomial x^2 - p (x + 1) - c

Alpha ( @ )
Beta ( ß )


x^2 - p ( x + 1 ) - c
x^2 - px - p - c
x^2 - px - (p+c)

Comparing with ax^2 + bx + c

a = 1
b = - p
c = - (p+c)

We know,

Alpha + Beta = - b/a = - (-p) = p
Alpha × Beta = c/a = - ( p+c )

Thus,

( Alpha + 1 ) ( Beta + 1 )
= @ß + @ + ß + 1
= - (p+c) + p + 1
= - p - c + p + 1
= 1 - c

Thus, ( Alpha + 1 ) ( Beta + 1 ) = 1 - c


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Hope it helps...!!!

Answer 2

Hey.....

here is your solution.....