Math, asked by khushisps, 1 year ago

prove it sec^2-sin^2/tan^2=cosec^2-cos^2

Answers

Answered by DonDj
7
HERE IA YOURS PROOF;

◆ If the LHS of the given equation is:

sec2a−sin2atan2a

=sec2atan2a−sin2atan2a

=1cos2a.cos2asin2a−sin2a.cos2asin2a

=1sin2a−cos2a=cosec2a−cos2a


​★ HENCE PROVED ★


HOPE IT HELPS
Answered by HDRocks
2
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