prove it sec^2-sin^2/tan^2=cosec^2-cos^2
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HERE IA YOURS PROOF;
◆ If the LHS of the given equation is:
sec2a−sin2atan2a
=sec2atan2a−sin2atan2a
=1cos2a.cos2asin2a−sin2a.cos2asin2a
=1sin2a−cos2a=cosec2a−cos2a
★ HENCE PROVED ★
HOPE IT HELPS
◆ If the LHS of the given equation is:
sec2a−sin2atan2a
=sec2atan2a−sin2atan2a
=1cos2a.cos2asin2a−sin2a.cos2asin2a
=1sin2a−cos2a=cosec2a−cos2a
★ HENCE PROVED ★
HOPE IT HELPS
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