if alpha and beta are the zeros of polynomial 3 X square + 5 x + 7 then find the value of 1 byalpha + 1 by beta
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this is example for u:
Let alpha and beta be the zeroes of p(x)=4x2+3x+7
Now, In Polynomial,
a=4, b=3 and c=7
Now,
alpha+beta= -b/a= -3/4
alpha*beta= c/a=7/4
Now, According to question,
alpha-1+beta-1
= (1/apha)+(1/beta)
= alpha+beta/alpha*beta --(By taking alpha*beta as LCM)
= (-3/4)/(7/4)
= -3/7
Required Answer--> -3/7
Hope It helps!
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