Question

If alpha and beta are the zeros of polynomial 8 x square + 2 x - 1 find the value of alpha/beta²-beta/alpha²?
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Answer 1

given quadratic eqn = 8x²+2x-1

by comparing with ax² + bx + c

[ a= 8, b= 2, c= -1]

bu using the formula -b +/- √b²- 4ac/2a

we get two roots alpha and beta

alpha = 1/4 , beta = -1/2

given alpha/beta²-beta/alpha²

substitute alpha and betha values

1/4 / (-1/2)² - (-1/2) / (1/4)²

1/4 / 1/4 + 1/2 / 1/16

after cancellation we get

1+8 = 9