if alpha and beta are the zeros of polynomial x^2-4x+3 form a quadratic polynomial whose zeros are 3 alpha and 3 Beta.
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Given α and β are zeroes of the polynomial f(x) = x2- 4x + 3
α+ β = 4 αβ = 3
Now,(3α + 3β) = 3x 4 = 12
3α x 3β = 9 x 3 = 27.
If 3α, 3β are zeros of the quadratic polynomial then the equation is
x2 -(3α + 3β)x + 9αβ = 0 then
x2 - 12x + 27 = 0.
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α+ β = 4 αβ = 3
Now,(3α + 3β) = 3x 4 = 12
3α x 3β = 9 x 3 = 27.
If 3α, 3β are zeros of the quadratic polynomial then the equation is
x2 -(3α + 3β)x + 9αβ = 0 then
x2 - 12x + 27 = 0.
Hope this will help you
Mark as brainliest if you like....
SahirulIslam:
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