Question

if alpha and beta are the zeros of polynomial x²-p(x+1) -c then (alpha+1) (beta+1) is equal to​

Answer 1

Step-by-step explanation:

Given,

α and β are the zeroes.

Given polynomial is;

= x²-p(x+1) -c;

From the polynomial, we can write;

α + β= p(x+1); (i)

and, αβ = -c; (ii)

We can write (α+1) (β+1) as;

= αβ + α + β + 1;

= αβ + (α + β) + 1; (iii)

From equation (i), (ii) and (iii);

= αβ + (α + β) + 1;

= (-c) + p(x + 1) + 1;

= px + p - c + 1

That's all.