Question

If alpha and beta are the zeros of quadratic polynomial p(x) = x2 - p( x + 1) - c, then (alpha+1) (beta+1) =?

Answer 1

(α+1)(β+1) = 1-c

Step-by-step explanation:

The given polynomial

$p(x)=x^2-p(x+1)-c$

or, $p(x)=x^2-px-(p+c)$

Since $\alpha$ and $\beta$ are zeroes of the polynomial $p(x)$

Therefore,

$\alpha+\beta=-(-p)=p$

And $\alpha\beta=-(p+c)$

Now,

$(\alpha+1)(\beta+1)$

$=\alpha\beta+\alpha+\beta+1$

$=-(p+c)+p+1$

$=1-c$

Hope this answer is helpful,

Know More:

Similar ques.

Click here:

https://brainly.in/question/1171203

https://brainly.in/question/3260457