if alpha and beta are the zeros of the given polynomial p(x) = 4x^2 - x - 4 . find alpha ^3 + beta^3
(class 10th maths chapter polynomial)
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To Find :-
- The value of α³ + β³.
Solution :-
Given,
- α and β are the zeroes of quadratic polynomial.
- Quadratic polynomial ; p(x) = 4x² - x - 4.
Given, p(x) = 4x² - x - 4
On comparing with ax² + bx + c , We get ;
↪ a = 4 , b = -1 , c = -4
Given, α and β are the zeroes of quadratic polynomial.
Sum of roots = -b/a
↪ α + β = -(-1)/4
↪ α + β = 1/4
Product of roots = c/a
↪ αβ = -4/4
↪ αβ = -1
Now, we need find the value of α³ + β³.
We know that,
α³ + β³ = (α + β)³ - 3αβ(α + β)
[ Put the values ]
↪ α³ + β³ = (1/4)³ - 3(-1)(1/4)
↪ α³ + β³ = 1/64 + 3 × 1 × 1/4
↪ α³ + β³ = 1/64 + 3/4
↪ α³ + β³ = 49/64
Therefore,
The value of α³ + β³ is 49/64.
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