Math, asked by 11111111Ayush1, 1 year ago

if alpha and beta are the zeros of the polynomial 2 X square + 6 x minus 3 then find the values of the expression a square + b square

Answers

Answered by EmadAhamed
13
↑ Here is your answer 
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Polynomial,

2x^2 + 6x - 3 = 0

We know,

 \alpha +  \beta = -b/a

Let alpha be 'a' and beta be 'B',

 \alpha  + \beta = -6/2

\alpha + \beta = -3

And,

\alpha \beta = c/a

\alpha \beta = -3/2

Now,

\alpha^2 + \beta^2

= (\alpha + \beta)^2 - 2 \alpha \beta

= (-3)^2 - 2*(-3/2)

= 9 + 3

= 12



EmadAhamed: anyway i got the same as yours :)
EmadAhamed: 12
11111111Ayush1: hahah
Swarup1998: It is not about the answer. You wrote polynomial = 0. Polynomial is an expression only. You could write it as equatio. Then the expression be valuing 0.
Swarup1998: nice answer bro
Swarup1998: keep it up
EmadAhamed: Bruh... i can't understand anything .-. anyways good answer! keep it up ^.^
Anonymous: nice presentation
EmadAhamed: Ty @chunchuni64 ^.^
Anonymous: :joy....
Answered by Swarup1998
6
The answer is given in the attachment.
Attachments:

Anonymous: nice handwriting bhaiya
Swarup1998: Thanks gungun...!
Anonymous: :wink
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