Question

If alpha and beta are the zeros of the polynomial p(x)= 4xsquare - 2x - 3 find the value of 1/alfa + 1/beta

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$\large{\underline{\underline{\mathfrak{\green{\sf{Answer--}}}}}}$.

$\bold{\frac{1}{-3}}$.

$\large{\underline{\mathfrak{\green{\sf{Given\:Here\:Equations--}}}}}$.

✴p(x)=4x² - 2x - 3.

$\bold{\:Here\alpha\:and\beta\:are\:root}$.

________So,

✴$\:Addition\:of\:Root\:=\frac{-Coffi. of x}{Coffi. of x^2}$.

$\implies\:Addition\:of\:root\:=\frac{-(-2)}{4}$.

$\implies\:(\alpha\:+\beta\:)\:=\frac{1}{2}$.....................(1).

✴$\:Multiply\:of\:root\:=\frac{constant part}{coffi. of x^2}$.

$\implies\:(\alpha\:×\beta\:)\:=\frac{-3}{2}$.................(2).

$\large{\underline{\underline{\mathfrak{\green{\sf{Find\:Here-}}}}}}$.

✴$\frac{1}{\alpha}\:+\frac{1}{\beta}$.

$\large{\underline{\underline{\mathfrak{\pink{\sf{Explanation-}}}}}}$.

$\implies\sf{\frac{1}{\alpha}\:+\frac{1}{\beta}}$.

$\implies\sf{\frac{\alpha+\beta}{\alpha\beta}}$.

➡Keep value by (1) and (2)

$\implies\sf{\frac{1/2}{-3/2}}$.

$\implies\sf{\frac{1}{2}\:×\frac{2}{-3}}$.

$\implies\sf{\frac{1}{-3}}$.

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