if alpha and beta are the zeros of the polynomial x is= 2X square + 5 x + k the equation relation alpha square +beta square + alpha beta is = 21 /
4 find the value of k
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Given:
★ A polynomial 2x²+5x+k .
★a²+ß² = 21/4
To Find:
★The value of k.
Concept Used:
★We will use some formulae realted to "quadratic polynomial".
Answer:
We have
Let p(x) = 2x²+5x+k .
w.r t Standard form ax²+bx+c ,
- a=2
- b=5 &
- c = k .
Now,we know,
If a & ß are zeroes then,
- a +ß =-b/a
- aß =c/a
so,
=> a² + ß² =²¹/4
=> a² + ß² + 2aß - 2aß =²¹/4
=>(a + ß )² =²¹/4+2aß
=>(-5/2)² = 21/4+2×k/2.
=> 25/4 =21/4+ k .
=>k = 25/4-21/4
=>k =4/4
.°. k = 1 .
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