if alpha and beta are the zeros of the polynomial x square - 3 x + 2 then find the value of Alpha Cube + beta cube
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3divided by 2 alpha +beta =3 divided by 2
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dnamdev12:
are (B) solve kar
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hello friends...
here given that
alpha and beta are roots of the equation
x² -3x +2
solution :-
we know that
the sum of roots = -b/a = coefficient of x / constant term
and
the product of alpha and beta = c/a = coefficient of x ² / constant term
here
alpha+ beta = -b/a = -(-3) /1 = 3
and
alpha× beta = c/a = 2/1 = 2
now
α +β = 3 & αβ =2,
we have to find
α³ + β³ = ?
we know that
a³+ b³ = (a+b)³ - 3ab(a+b)
=> α³ +β³ = (α+β)³ -3αβ(α+β)
= 3³ - 3 ×2×3 = 27 - 18 = 9 answer
♦ hope it helps ♦
here given that
alpha and beta are roots of the equation
x² -3x +2
solution :-
we know that
the sum of roots = -b/a = coefficient of x / constant term
and
the product of alpha and beta = c/a = coefficient of x ² / constant term
here
alpha+ beta = -b/a = -(-3) /1 = 3
and
alpha× beta = c/a = 2/1 = 2
now
α +β = 3 & αβ =2,
we have to find
α³ + β³ = ?
we know that
a³+ b³ = (a+b)³ - 3ab(a+b)
=> α³ +β³ = (α+β)³ -3αβ(α+β)
= 3³ - 3 ×2×3 = 27 - 18 = 9 answer
♦ hope it helps ♦
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