if alpha and beta are the zeros of the polynomial x2-2x-8, then form a quadratic polynomial whose zeroes are 2alpha and 2bita
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x²-2x-8=x²-4x+2x-8=(x-4)x+2(x-4)=(x+2)(x-4)
now solve,
x+2=0,x-4=0
x = -2, x = +4
then 2alpha and 2beta
solve your self
now solve,
x+2=0,x-4=0
x = -2, x = +4
then 2alpha and 2beta
solve your self
Laxmireddyreddy:
ok thnx
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hope you like answer
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