Question

if alpha and beta are the zeros of the polynomial x²+ 6x + 2 , then find the value of (1/alpha + 1/beta )​

Answer 1

Step-by-step explanation:

α and β are the roots of the quadratic equation x^2 + 6x + 2

$\alpha + \beta = - \frac{b}{a} = - \frac{6}{1} = - 6$

$\alpha \times \beta = \frac{c}{a} = \frac{2}{1} = 2$

$\frac{1}{ \alpha } + \frac{1}{ \beta }$

$= \frac{ \beta + \alpha }{ \alpha \beta }$

$= \frac{ \alpha + \beta }{ \alpha \beta }$

$= - \frac{6}{2}$

$= - 3$

Answer 2

Answer:

See the picture above.. Hope it will help you.