Question

if alpha and beta are the zeros of the quadratic polynomial x square - 5 x + 6 find the value of one upon alpha plus one upon beta minus 2 alpha beta

Answer 1

Answer:

Step-by-step explanation:

P(x) = x^2 -5x + 6

Sum 9f zeroes = alfa + beta = -b/a = 5/1

Product of zeroes = alfa × beta = c/a = 6/1

Now we need to find the value of 1/ alfa + 1/beta - -2 alfa beta

= ([beta + alfa) / alfa beta - 2 alfa beta]

Substitute the value of alfa+beta and alfa beta, we get

5/6 -2×6

=5/6 -12

=(5 -72)/6

=-67/6