Question

if alpha and beta are the zeros of the quadratic polynomial 5 Y square minus 7 Y + 1 find the value of one by Alpha Plus One by beta​

Answer 1

$\Rightarrow\Huge\boxed{\frac{7}{1}}$

$\huge\underline\mathfrak\purple{Answer}$

$5 {y}^{2} - 7y + 1. \\ \\ \alpha + \beta = \frac{ - b}{a} . \\ \\ \: \: \: \: \: \: \: \: \: \: \: \: = \frac{7}{5} . \\ \\ \alpha . \beta = \frac{c}{a} . \\ \\ \: \: \: \: \: \: \: \: = \frac{1}{5} . \\ \\ so \\ \\ \: = \frac{1}{ \alpha } + \frac{1}{ \beta } \\ \\ = \frac{ \alpha + \beta }{ \alpha . \beta } \\ \\ = \frac{7}{5} \times \frac{5}{1} \\ \\ = \cancel \frac{35}{5} . \\ \\ = 7$

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