if alpha and beta are the zeros of the quadratic polynomial such that alpha + beta is equal to 24 and Alpha minus theta is = 8 find the quadratic polynomial having alpha and beta
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alpha+beta=24
alpha-beta=8
2alpha=32(elimination)
alpha=16
beta=24-16
beta=8
now,
alpha +beta=32
alpha×beta=16×8=128
therefore,
the polynomial is given by,
k{x^2-(sum of zeroes)x+(product of zeroes)}
k{x^2 - 32x + 128}
the polynomial is x^2-32x+128,where k=1
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