Question

if alpha and beta are the zeros of the quadratic polynomial x2-6x+k find the value of k if alpha+beta whole square-2(alpha*beta)

Answer 1

Answer:

k=-2

Step-by-step explanation:

The given equation is:

x^2-6x+k, comparing this equation with ax^2 + bx + c , we have a=1, b=-6, c=k.

Now, if α and β arethe two zeroes of the given polynomial, then α+β= -b/a and αβ= c/a = k

Also, it is given that

⇒alpha^2 + beta^2 = 40

⇒alpha^2 + beta^2 = (alpha+ beta)^2 - 2alpha beta

⇒40=6^2-2k

⇒k = -2