If alpha and beta are the zeros of the quadratic polynomial,f(x) =6x^2+x-2,then find the value of alpha cube +beta cube ?
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Step-by-step explanation:
Given -
- α and β are zeroes of polynomial f(x) = 6x² + x - 2
To Find -
- Value of α³ + β³
Now,
→ 6x² + x - 2
By middle term splitt :-
→ 6x² + 4x - 3x - 2
→ 2x(3x + 2) - 1(3x + 2)
→ (2x - 1)(3x + 2)
Zeroes are -
→ 2x - 1 = 0 and 3x + 2 = 0
→ x = 1/2 and x = -2/3
Then, The value of α³ + β³ is
→ (1/2)³ + (-2/3)³
→ 1/8 - 8/27
→ 27 - 64/216
→ -37/216
Hence,
The value of α³ + β³ is -37/216
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