Question

If alpha and beta are the zeros of the quadratic polynomial 3 X square +8 x +2 find the value of Alpha 3 +beta 3

Answer 1

Answer:

Step-by-step explanation:

3x² - 8x + 2

α + β = (-coefficient of x / coefficient of x²)

α + β =  -(-8)/3 = 8/3

αβ = (coefficient of constant term / coefficient of x²)

αβ = (2/3) = 2/3

α³ + β³

= (α+β)³ - 3αβ(α+β)

= (8/3)³ - 3(2/3)(8/3)

= (8/3)³ - 2(8/3)

= 8/3*((8/3)² - 2)

= 8/3( 64/9 - 2)

= 8/3 (46/9)

= 368/27