if alpha and beta are the zeros of the quadratic polynomial FX equal to x square - 2 X + Q prove that Alpha^/beta^+alpha^=p^^/q^-4p^/q+2
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if alpha and beta are zeroes of the quadratic polynomial f x 3x 5x 2 then evaluatealpha beta q2 if one of the zeroes of the cubic polynomial x ax hzek1hdd
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Step-by-step explanation:
To prove:
α²/β² + β²/α² = p⁴/q² - 4p²/q + 2
Taking LCM on LHS and RHS, we get:
(α⁴ + β⁴)/(α²β²) = (p⁴ - 4p²q + 2p²) / q² --(i)
Now, we know,
α and β are the two zeroes of the polynomial p(x) = x² - px + q
Therefore, on expressing the polynomial in the form ax² + bx + c,
α + β = -b/a = -p/1 = -p
And,
αβ = c/a = q/1 = q
We know can find the value of α⁴ + β⁴ by squaring α + β tow times as in the attached image and find α²β² and then plug it into equation (i) and then we get LHS = RHS
Refer to the attached images. :D
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