If alpha and beta are the zeros of x^2-1,find a quadratic polynomial whose zeros are 2(alpha)/beta and 2(beta)/alpha
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Answer:
x²-(-4)x+4
Step-by-step explanation:
we will let, x²-1= x²-x-1 because to complete the polynomial.
now we have alpha+beta=1
alpha ×beta=-1
now sum of zeroes
2a/b + 2b/a = see photo
& product of zeroes
2a/b + 2b/a = 4ab/ab
= 4(-1)/-1
=4
So the polynomial is above in answer.
that's what I think can be, i hope this would help you...
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