if alpha and beta are the zeros of x square + 7x + 12 then find the value of one upon alpha + one upon beta minus 2 alpha beta
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Given
p(x)= x²+7x+12
here,
a= 1, b= 7 and c= 12
we know that,
sum of zeroes= -b/a
_______________(1)
also,
Product of zeroes= c/a
__________________(2)
now,
from (1) and (2), we have,
p(x)= x²+7x+12
here,
a= 1, b= 7 and c= 12
we know that,
sum of zeroes= -b/a
_______________(1)
also,
Product of zeroes= c/a
__________________(2)
now,
from (1) and (2), we have,
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