If alpha and beta are two numbers such that alpha plus beta is equal to 16 and Alpha minus beta is equal to 4 then form a quadratic polynomial whose zeros are alpha and beta
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Answer:
x² - 16x + 160
alpha + beta =16 _ 1
alpha -beta=4 _ 2
alpha =16-beta
Substitute value of alpha in eq 2
16 - beta - beta= 4
16 - 2 beta = 4
- 2 beta = - 20
beta = 10
alpha + 10 = 16
alpha = 6
alpha × beta = 160
polynomial, x² - 16x + 160
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