Question

If alpha and beta are zeroes of 2x^2+5x+1 then evaluate alpha^2+beta^2

Answer 1

Step-by-step explanation:

p(x)=2x^2 +5x+1

Here,a=2,b=5 and c=1

alpha + beta= -b/a

= -5/2

alpha×beta=c/a

=1/2

alpha^2+beta^2=(alpha+beta)^2- 2×alpha×beta

=(-5/2)^2 -2×1/2

=25/4-1

=21/4

Hence,alpha ^2+beta^2=21/4