Question

If /alpha and /beta are zeroes of a polynomial then form a quadric polynomial, such that
$\alpha + \beta = 8$,
$\alpha - \beta = 2$
​

Answer 1

Answer:

X^2-(ALPHA+BETA) X+(ALPHA ×BETA)

ALPHA +BETA =8

ALPHA -BETA=2

BETA = 3

ALPHA =5

NOW,

ALPHA×BETA=15

X^-8X+15=0