if alpha and beta are zeroes of polynomial 4x^2+3x+7,so find the value (i) alpha^2+beta^2
Answers
Answered by
21
Answer:
α² + β² is –47/16.
Step-by-step explanation:
Given Polynomial = 4x² + 3x + 7
Value of α² + β² = ??
In the polynomial,
- a = 4
- b = 3
- c = 7
Sum of zeros -
α + β = –b/a
α + β = –3/4
Product of zeros -
αβ = c/a
αβ = 7/4
★ Value of α² + β² :
α² + β²
(α + β)² – 2αβ
(–3/4)² – 2(7/4)
9/16 – 7/2
9/16 – 56/16
–47/16
Therefore, α² + β² is –47/16.
Answered by
2
Answer:
In the polynomial,
a = 4
b = 3
c = 7
Sum of zeros -
α + β = –b/a
α + β = –3/4
Product of zeros -
αβ = c/a
αβ = 7/4
now Value of α² + β² :
α² + β²
(α + β)² – 2αβ
(–3/4)² – 2(7/4)
9/16 – 7/2
9/16 – 56/16
–47/16
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