If alpha and beta are zeroes of polynomial ax^2+bx+c then,evaluate1)1 by alpha+1 by beta-2alphabeta
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Hi there !!!
Refer to this link for the answer ...
I have previously answered it :-
https://brainly.in/question/1248125
Refer to this link for the answer ...
I have previously answered it :-
https://brainly.in/question/1248125
Answered by
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Hi friend!!
α and ß are the zeroes of the quadratic polynomial ax²+bx+c
We know the relationship between zeroes and coefficients,
Sum of zeroes = -b/a
α+ß = -b/a
Product of zeroes = c/a
αß = c/a
→ 1/α + 1/ß - 2αß
→ (ß+α)/αß - 2αß
→ (-b/a)/c/a - 2(c/a)
→ -b/c - 2c/a
→ (-ba - 2c²)/ac
Hope it helps...
α and ß are the zeroes of the quadratic polynomial ax²+bx+c
We know the relationship between zeroes and coefficients,
Sum of zeroes = -b/a
α+ß = -b/a
Product of zeroes = c/a
αß = c/a
→ 1/α + 1/ß - 2αß
→ (ß+α)/αß - 2αß
→ (-b/a)/c/a - 2(c/a)
→ -b/c - 2c/a
→ (-ba - 2c²)/ac
Hope it helps...
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