Question

If alpha and beta are zeroes of polynomial x^2+6x+a then find the value of a in 3alpha +2beta=20

Answer 1

Answer:

a=-6

x^2+6x+a

alpha+ beta =-b/a

=-6

alpha=6-beta

3 alpha+2beta=20

3 (-6-beta )+2beta=20

-18-3beta+2beta=20

-18-beta=20

-18-20=beta

beta= -38

alpa=6+38

alpa=44

alpha×beta=c/a

alpha×beta =44×38

=1672

a=1672