If alpha and beta are zeroes of polynomial x square+six x +9,then form a polynomial whose zeroes are - alpha and -beta?
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Answer: if α & βare the zeroes of polynomial
x²+6x+9
= x²+3x+3x+9
= x(x+3)+3(x+3)
= (x+3)(x+3)
x = -3 ,x=-3
α= -3 ,β=-3
If
α=-3 then -α=3
β=-3 then -β=3
Now,
(x-3)(x-3)
= x²-3x-3x+9
=x²-6x+9
Therefore the equation is
x²-6x+9
Step-by-step explanation:
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